70b^2+590b+240=0

Solution for 70b^2+590b+240=0 equation:

70b^2+590b+240=0

a = 70; b = 590; c = +240;
Δ = b2-4ac
Δ = 5902-4·70·240
Δ = 280900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{280900}=530$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(590)-530}{2*70}=\frac{-1120}{140}
=-8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(590)+530}{2*70}=\frac{-60}{140}
=-3/7
$